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 ¦nÃø³á¡I

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ÃÒ©ú¡G¤G+¤T¦¸®Ú¸¹¤C¤p©ó¤T¦¸®Ú¸¹¤»¤Q

 2006-06-04 00:31
linian
Home away from home



µù¥U¤é: 2005-11-07
µoªí¼Æ: 292


 Re: ¦nÃø³á¡I

1.
A^3+B^3+C^3-3ABC=
(A+B+C)(A^2+B^2+C^2-AB-BC-CA)(¦]¦¡¤À¸Ñ)
=(A+B+C)(2A^2+2B^2+2C^2-2AB-2BC-2CA)*1/2
=(A+B+C)((A-B)^2+(B-C)^2+(C-A)^2)*1/2
¤S)((A-B)^2+(B-C)^2+(C-A)^2)*1/2¤j©ó0
©Ò¥H
A^3+B^3+C^3-3ABC»P(A+B+C)¦P¸¹


_________________
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 2006-06-04 09:47­Ó¤H¸ê®Æ¶Ç°e Email µ¹ linian«ô³Xºô¯¸
fuyaen
Just can't stay away



µù¥U¤é: 2006-05-30
µoªí¼Æ: 84


 Re: ¦nÃø³á¡I

³o¬O¤p¾ÇªºÃD¥Ø?
¤£·|§a
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 2006-06-04 12:05­Ó¤H¸ê®Æ«ô³Xºô¯¸
³X«È








 Re: ¦nÃø³á¡I

¬°¦ó¡i(A-B)^2+(B-C)^2+(C-A)^2¡j*1/2¤j©ó0©O¡H

 2006-06-04 17:17
j7631103
Home away from home



µù¥U¤é: 2005-03-06
µoªí¼Æ: 490


 Re: ¦nÃø³á¡I

¤Þ¤å:

1123581321 ¼g¹D:
¬°¦ó¡i(A-B)^2+(B-C)^2+(C-A)^2¡j*1/2¤j©ó0©O¡H


³o¬O¤T¼Æ¥­¤è,¥BA,B,C¬°¬Û²§¹ê¼Æ©Ò¥H¥L¤j©ó0

 2006-06-04 17:31­Ó¤H¸ê®Æ¶Ç°e Email µ¹ j7631103
³X«È








 Re: ¦nÃø³á¡I

±i¯Õ°·ÁÂÁÂ

 2006-06-04 17:42


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