N is a natural number such that when divided by 10 it leaves the remainder 9, when divided by 9 it leaves the remainder 8, when divided by 8 it leaves the remainder 7, ...., when divided by 2 it leaves the remainder 1. Find the smallest value of N.
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phi112358132134

2008-01-28 20:59
有一自然數N,被10除餘9,被8除餘7......,被2除餘1,求N最小值
被a除餘(a-1)就是缺1,因此N為10至2的最小公因數減1
(10,9,8,7,6,5,4,3,2)=1260
1260-1=1259
A: :lspeak:1259

crazytrquan

2008-01-30 09:42
最小公因數???應是最小公倍數吧!!