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 ¸Ñ¤èµ{¦¡

¡Ô(5x^2-6x+1)+ ¡Ô(5x^2+9x-2)=5x-1

 2005-07-20 13:38
ej0cl6
Home away from home



µù¥U¤é: 2005-03-03
µoªí¼Æ: 281
¡© ² ¡ª ªº ¬G ¶m

 Re: ¸Ñ¤èµ{¦¡

¡Ô(5x^2-6x+1)+¡Ô(5x^2+9x-2)=5x-1
==>¡Ô[(5x-1)(x-1)]+¡Ô[(5x-1)(x+2)]=5x-1
¥O5x-1=y
¡Ô[y(x-1)]+¡Ô[y(x+2)]=y
==>y(x-1)+2¡Ô[y^2(x-1)(x+2)]+¡Ô(x-2)=y^2
yx-y+2y¡Ô(x-1)(x+2)]+¡Ô(x-2=y^2)
==>x-1+2¡Ô[(x-1)(x+2)]+x+2=y
y¤w5x-1±a¦^¥h
2x+1+2¡Ô[(x-1)(x+2)]=5x-1
2¡Ô[(x-1)(x+2)]=3x-2
==>4(x-1)(x+2)=(3x-2)^2
4(x^2+2x-x-2)=9x^2-12x+4
4x^2+4x-8=9x^2-12x+4
5x^2-16x+12=0
(5x-6)(x-2)=0
x=6/5 or 2

¤£ª¾¹D¹ï¤£¹ï^^


_________________

http://blog.pixnet.net/ej0cl6
¡ô³o¬O³Ìªñ¦¨¥ßªº¼Æ¾ÇBLOG
¡@¸Ì­±¦³¨Ç´X¦óªºªF¦è
¡@¤j®a¥i¥H°ÑÆ[¬Ý¬Ý©O

 2005-07-20 16:46­Ó¤H¸ê®Æ«ô³Xºô¯¸
felixhsieh
Just popping in



µù¥U¤é: 2007-01-26
µoªí¼Æ: 17
­ß¤ý¬P

 Re: ¸Ñ¤èµ{¦¡

¡Ô(5x^2-6x+1)+ ¡Ô(5x^2+9x-2)=5x-1
¡Ô[(5x-1)(x-1)]+¡Ô[(5x-1)(x+2)]=5x-1
(¡Ô(5x-1))(¡Ô(x-1)+¡Ô(x+2))=5x-1
¡Ô(x-1)+¡Ô(x+2)=¡Ô(5x-1)
2x+1+2¡Ô((x-1)(x+2))=5x-1
2¡Ô((x-1)(x+2))=3x-2
4x^2+4x-8=9x^2-12x+4
5x^2-16x+12=0
x=(16¡Ó4)/10
x=2 or 6/5

¥N¦^­ì¤èµ{¦¡(³o¬O¸Ñ®Ú¦¡¤èµ{«Ü­«­nªº¤@¨B!)
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_________________
¼Æ¾Ç®a¬O¤@³¡¥Î¨Ó±N©@°ØÂà´«¦¨©w²zªº¾÷¾¹¡C
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¼Æ¾Ç®a¬O¤@³¡¥Î¨Ó±N¯ùÂà´«¦¨©w²zªº¾÷¾¹¡C
---§Ú

 2007-01-27 17:19­Ó¤H¸ê®Æ
71727
Just popping in



µù¥U¤é: 2006-02-13
µoªí¼Æ: 9


 Re: ¸Ñ¤èµ{¦¡

¡Ô(5x^2-6x+1)+ ¡Ô(5x^2+9x-2)=5x-1
¡Ô[(5x-1)(x-1)]+¡Ô[(5x-1)(x+2)]=5x-1
¡Ô(x-1)+¡Ô(x+2)=¡Ô(5x-1)
2x+1+2¡Ô((x-1)(x+2))=5x-1
2¡Ô((x-1)(x+2))=3x-2
5x^2-16x+12=0
x=2 or 6/5

 2007-01-28 13:46­Ó¤H¸ê®Æ
black
Just popping in



µù¥U¤é: 2007-01-14
µoªí¼Æ: 6


 Re: ¸Ñ¤èµ{¦¡

¡Ô(5x^2-6x+1)+¡Ô(5x^2+9x-2)=5x-1
¡Ô[(5x-1)(x-1)]+¡Ô[(5x-1)(x+2)]=5x-1
¥O5x-1=A
¡Ô[A(x-1)]+¡Ô[A(x+2)]=A
A(x-1+X+2)+2¡Ô[A^2(x-1)(x+2)]=A^2
2Ax+A+2A¡Ô(x-1)(x+2)]=A^2
2x+1+2¡Ô(x^2+x-2)=A
±a¤JA=5x-1
5x^2-16x+12=0
x=2©Î6/5

 2007-02-09 22:11­Ó¤H¸ê®Æ
David
Just can't stay away



µù¥U¤é: 2006-04-09
µoªí¼Æ: 101


 Re: ¸Ñ¤èµ{¦¡

¡Ô(5x-1)(x-1)+¡Ô(5x-1)(x+2)=5x-1
¥Oy=5x-1
¡Ôy(x-1)+¡Ôy(x+2)=y
¨âÃ䥭¤è
y(x-1)+2¡Ôy^2(x-1)(x+2)+y(x+2)=y^2
y(2x+1)+2¡Ôy^2(x-1)(x+2)=y^2
2¡Ôy^2(x-1)(x+2)=y(y-2x-1)
¥N¤Jy=5x-1
2¡Ôy^2(x-1)(x+2)=y(3x-2)
¨âÃ䥭¤è
4y^2(x-1)(x+2)=y^2(9x^2-12x+4)
y^2[4(x-1)(x+2)-(9x^2-12x+4)]=0
¥N¤Jy=5x-1
(5x-1)^2(5x^2-16x+12)=0
(5x-1)^2(x-2)(5x-6)=0
x=1/5, 2, 5/6

¦³¤T¸Ñ1/5, 2, 5/6

 2007-02-10 14:15­Ó¤H¸ê®Æ
frog
Just can't stay away



µù¥U¤é: 2006-02-28
µoªí¼Æ: 114


 Re: ¸Ñ¤èµ{¦¡

µ¥¦¡¨âÃ䤣¥i¥ô·N®ø¥h¬Y£¸¤½¦]¦¡
§_«h·|µo¥Í´î®Úªº±¡§Î
¨Ò¦p:
(5x-1)f(x)=(5x-1)g(x)
¦¹¤èµ{¦¡¥»¨Ó¦³£¸®Ú¬°x=1/5,¦ý­Y¥ý¦P®É°£¥H5x-1,«h¸Ñ¥X¨Óªº®Ú±N¯Ê¤Öx=1/5³o­Ó®Ú
©Ò¥H¤W­z¨Ò¤lÀ³¥ý±N5x-1´£¥X
§Y(5x-1)[f(x)-g(x)]=0
«h5x-1=0, f(x)-g(x)=0

 2007-02-10 17:19­Ó¤H¸ê®Æ


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