| 發布者 | 內容列 |
ej0cl6
Home away from home
註冊日: 2005-03-03
發表數: 281
〝 � 〞 的 故 鄉
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 2005-12-07 19:29 |   |
訪客
| | Re: 高斯函數一題.. |  | 假設x是解，且n=[x]，因此x^2+7=8n，n≧0
由n≦x＜n+1，得n^2+7≦x^2+7＜(n+1)^2+7
n^2+7≦8n＜n^2+2n+8
解得n=1,5,6,7代回x^2+7=8n中得x=1,√33,√41,7
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| 2005-12-07 19:54 | |
linian
Home away from home
註冊日: 2005-11-07
發表數: 292
| | Re: 高斯函數一題.. | | 引文:
寫道:
假設x是解，且n=[x]，因此x^2+7=8n，n≧0
由n≦x＜n+1，得n^2+7≦x^2+7＜(n+1)^2+7
n^2+7≦8n＜n^2+2n+8
解得n=1,5,6,7代回x^2+7=8n中得x=1,√33,√41,7
請問如何解n^2+7≦8n＜n^2+2n+8
_________________
KH~~
この空がつなぐ世界で
辿り𤥢く場所は
一緒だと信じています
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| 2005-12-07 22:05 |  |
訪客
| | Re: 高斯函數一題.. | | n^2+7≦8n＜n^2+2n+8
n^2+7≦8n且8n＜n^2+2n+8
n^2-8n+7≦0且n^2-6n+8＞0
(n-1)(n-70且(n-2)(n-4)＞0
1≦n≦7且(n＞4或n＜2)
1≦n＜2或4＜n≦7
又n是整數，所以n=1,5,6,7 |
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| 2005-12-08 09:20 | |
dhfurjk
Not too shy to talk
註冊日: 2005-09-03
發表數: 23
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| 2005-12-08 23:01 | |
訪客
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| 2005-12-09 19:44 | |
ej0cl6
Home away from home
註冊日: 2005-03-03
發表數: 281
〝 � 〞 的 故 鄉
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| 2005-12-09 22:23 | |
mathematical2005
Just can't stay away
註冊日: 2005-05-17
發表數: 117
China
| | Re: 高斯函數一題.. | | 這一題也可用畫圖來解吧
_________________
The art of doing mathematics consists in finding that special case which contains all the germs of generality 
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| 2006-02-08 13:59 | |
linian
Home away from home
註冊日: 2005-11-07
發表數: 292
| | Re: 高斯函數一題.. | | 可以示範如何畫嗎
_________________
KH~~
この空がつなぐ世界で
辿り𤥢く場所は
一緒だと信じています
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| 2006-02-08 18:15 | |
bill2002
Just can't stay away
註冊日: 2002-12-29
發表數: 71
偉大的地球
| | Re: 高斯函數一題.. | | 一定要這麼複雜嗎
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數學有好玩之處，大家一起愛數學吧!
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| 2006-02-09 00:07 | |
