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 ¦]¦¡¤À¸Ñ

¦]¦¡¤À¸Ñ x^3 + y^3 + 3xy - 1

 2006-02-05 19:26
ac19920221
Quite a regular



µù¥U¤é: 2006-01-13
µoªí¼Æ: 49


 Re: ¦]¦¡¤À¸Ñ

(x+y-1)(x^2-xy+y^2+x+y+1)

 2006-02-05 19:30­Ó¤H¸ê®Æ
ej0cl6
Home away from home



µù¥U¤é: 2005-03-03
µoªí¼Æ: 281
¡© ² ¡ª ªº ¬G ¶m

 Re: ¦]¦¡¤À¸Ñ

x^3+y^3+3xy-1
=(x+y)^3-3xy(x+y)+3xy-1
=(x+y-1)(x^2+2xy+y^2+x+y+1)-3xy(x+y-1)
=(x+y-1)(x^2-xy+y^2+x+y+1)


_________________

http://blog.pixnet.net/ej0cl6
¡ô³o¬O³Ìªñ¦¨¥ßªº¼Æ¾ÇBLOG
¡@¸Ì­±¦³¨Ç´X¦óªºªF¦è
¡@¤j®a¥i¥H°ÑÆ[¬Ý¬Ý©O

 2006-02-05 21:28­Ó¤H¸ê®Æ«ô³Xºô¯¸
aa963854116
Home away from home



µù¥U¤é: 2006-01-06
µoªí¼Æ: 392
±q¥¼µo²{¤§89¸¹¬P®y

 Re: ¦]¦¡¤À¸Ñ

§Q¥Îa^3+b^3+c^3-3abc
=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)
¨úa=x,b=y,c=-1§Y¥i
³o¬O¤@­Ó¦n¥Îªº¤½¦¡

 2006-02-06 09:28­Ó¤H¸ê®Æ
kc81731
Quite a regular



µù¥U¤é: 2006-01-30
µoªí¼Æ: 43
C组

 Re: ¦]¦¡¤À¸Ñ

x^3+y^3+3xy-1
=(x+y)^3-3xy(x+y)+3xy-1
=(x+y-1)(x^2+2xy+y^2+x+y+1)-3xy(x+y-1)
=(x+y-1)(x^2-xy+y^2+x+y+1)


_________________

 2006-02-06 11:25­Ó¤H¸ê®Æ
qqwwee2006
Just can't stay away



µù¥U¤é: 2006-02-18
µoªí¼Æ: 79
¤õ¬P

 Re: ¦]¦¡¤À¸Ñ

µª®×....(x+y-1)(x^2-xy+y^2+x+y+1)


_________________
dodo61411@yahoo.com.tw
§Ú¥u¬O­]¤pªº¥®¯ó~~!

 2006-02-23 22:48­Ó¤H¸ê®Æ¶Ç°e Email µ¹ qqwwee2006
mathematical2005
Just can't stay away



µù¥U¤é: 2005-05-17
µoªí¼Æ: 117
China

 Re: ¦]¦¡¤À¸Ñ

x^3+y^3+3xy-1
=(x+y)^3-3xy(x+y)+3xy-1
=(x+y-1)(x^2+2xy+y^2+x+y+1)-3xy(x+y-1)
=(x+y-1)(x^2-xy+y^2+x+y+1)


_________________
The art of doing mathematics consists in finding that special case which contains all the germs of generality

 2006-02-24 00:02­Ó¤H¸ê®Æ
m=dv
Not too shy to talk



µù¥U¤é: 2006-01-06
µoªí¼Æ: 21


 Re: ¦]¦¡¤À¸Ñ

(x+y-1)(x^2-xy+y^2+x+y+1)


_________________

·í­Ó·R°Ý°ÝÃDªº"°ÝÃD¨àµ£"§a~~

 2006-02-28 14:59­Ó¤H¸ê®Æ
³X«È








 Re: ¦]¦¡¤À¸Ñ

(x+y-1)(x^2-xy+y^2+x+y+1)

 2006-02-28 17:54
94006
Home away from home



µù¥U¤é: 2005-09-20
µoªí¼Æ: 161
ªZ³®°ª¤¤

 Re: ¦]¦¡¤À¸Ñ

(x+y-1)(x^2-xy+y^2+x+y+1)


_________________
±ý³t«h¤£¹F

 2006-02-28 17:55­Ó¤H¸ê®Æ


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