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linian
Home away from home



µù¥U¤é: 2005-11-07
µoªí¼Æ: 292


 ¦³ÃöÂù¶g¤@ÃD²Ä¤KÃDªº¦Wµü

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¤@ºüÇGÇO«HÆþÇMÆêÇeÇ@

 2006-12-30 21:37­Ó¤H¸ê®Æ¶Ç°e Email µ¹ linian«ô³Xºô¯¸
felixhsieh
Just popping in



µù¥U¤é: 2007-01-26
µoªí¼Æ: 17
­ß¤ý¬P

 Re: ¦³ÃöÂù¶g¤@ÃD²Ä¤KÃDªº¦Wµü

¬O«ü«Ê³¬°Ï¶¡¶Ü?
[a,b]
a¡Øx¡Øb

ÂI§Ú

¬Ý¹LÃD¥Ø¤F¡A¶W¥X§Úªº½d³ò


_________________
¼Æ¾Ç®a¬O¤@³¡¥Î¨Ó±N©@°ØÂà´«¦¨©w²zªº¾÷¾¹¡C
---«Où¡E¤Ì¦h´µ
¼Æ¾Ç®a¬O¤@³¡¥Î¨Ó±N¯ùÂà´«¦¨©w²zªº¾÷¾¹¡C
---§Ú

 2007-01-27 17:26­Ó¤H¸ê®Æ
math120908
Not too shy to talk



µù¥U¤é: 2005-08-23
µoªí¼Æ: 34


 Re: ¦³ÃöÂù¶g¤@ÃD²Ä¤KÃDªº¦Wµü

«Ê³¬ªí¹F¦¡ «üªºÀ³¸Ó¬O­Y­n¨DF(x)ªº«Ê³¬ªí¹F¦¡
«h©Òªí¹Fªº¤èµ{¦¡¤£¯à¥X²{F(g(x))...§a
¦³ÂIÃøÀ´
´«¥y¸Ü»¡ ¤]´N¬O"³q¶µ¤½¦¡"
§â¨ç¼Æ¤èµ{¦¡ ¤Æ² Åܦ¨¥u¦³¤@¶µF(x) ¦Ó¤£·|¦P®É¶]¥XF(x+1) ©ÎF(F(x))³o¼Ë¤lªº¦¡¤l

¨Ò¦p»¡Fibonacci¼Æ¦C¥i¥Hªí¥Ü¦¨
(1)F(0)=F(1)=1
(2)F(n)=F(n-1)+F(n-2)
¥i¬O«á¦¡¨Ã«D«Ê³¬ªí¹F
¦ÓÅܦ¨¤@»¼°j¨ç¼Æ

¦³¤H´£¥X¨ÓFibonacci¼Æ¦Cªº³q¶µ¤½¦¡¬°
F(n)=(1/¡Ô5)*(£X^n - £p^n)
¨ä¤¤£X,£p¬°¶Àª÷¤ñ
¦Ü©óÃÒ©ú
¦³¿³½ìªº¸Ü¤E³¹ªº"±q¥¿¤­Ãä§Î½Í°_"¸Ì¦³»¡¨ì...¥i¥H°Ñ¦Ò

¦^Âk¥¿ÃD ¥H¤Wªº³o­Ó¦¡¤lFibonacci¼Æ¦Cªº³q¶µ¤½¦¡
À³¸Ó«üªº´N¬OF(n)ªº«Ê³¬ªí¹F¦¡....
³o¼Ë¤l¦³¨S¦³²M·¡¤@ÂI¤F©O??



_________________
If I have seen farther, it is by standing on the shoulders of the giants.---Newton

 2007-02-01 20:16­Ó¤H¸ê®Æ
isomorphism
Not too shy to talk



µù¥U¤é: 2007-01-30
µoªí¼Æ: 40


 Re: ¦³ÃöÂù¶g¤@ÃD²Ä¤KÃDªº¦Wµü

As 'math' said above, I believe it means a closed form expression, one that does not rely on sigma or pi notation.

 2007-02-01 22:04­Ó¤H¸ê®Æ


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