http://math1.ck.tp.edu.tw/³q°T¸ÑÃD/doc/question53.doc²Ä¤@ÃD¡AÁÂÁ¡I
¾ã²z«á¡G(11-x)^5+(11-x)=-5(y-4)^5+(y-4)=-5(11-x)^5+(11-x)=(y-4)^5+(y-4)(11-x)=(y-4)x+y=15
danny830401 ¼g¹D:¾ã²z«á¡G(11-x)^5+(11-x)=-5(y-4)^5+(y-4)=-5(11-x)^5+(11-x)=(y-4)^5+(y-4)(11-x)=(y-4)x+y=15
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³]A=x-11,B=y-4,¥BA,B¤£µ¥©ó0A(A^4+15)=5,¦]A^4¤j©ó0¬GA¬°±µªñ1/3¤§¥¿¼Æ¦P²zB¬°±µªñ-1/3¤§t¼Æ,¨â¦¡¬Û¥[¤À¸Ñ«á±o(A+B)[A^4+A^2B^2+B^4-AB(A^2+B^2)+15]=0¦]-AB¤j©ó0,¬G[....]¬°¥¿¼Æ¬GA+B=0,¥N¤J즡±ox+y=15