小六學生問的...分數難題

運用分項對消的概念便可輕鬆解題

抱歉看錯了,我再看看

這題被問過好幾次，但問的人也都沒答案
這題化簡後似乎和調和級數和類似
能以一般代數方法解出實際的數字嗎？？
懷疑中…是否有高手能提供些意見呢?
感激不盡

只要挑出幾項出來運算就知道這一題是瞎掰的
不會有特殊代數解法,只是大家不敢說出來
但如果認真去解這一題
仍然會得到很大的樂趣
因為電腦和計算機10位數以上運算就會有困難
如果直接以分母連乘積為公分母
得到的分子和分母是5749位數
經過約分後得到的分子是866位數
求得n=
89,4381,5998,8503,7311,8805,5793,
5109,8024,1396,0466,5067,3037,7931,
6392,1006,8914,8346,5535,2880,4165,
0914,9670,5673,9575,5321,5922,3588,
0035,3661,7279,1966,5999,7300,6802,
1782,2894,3859,6427,2343,4745,7746,
7145,4492,9156,9357,3814,4794,1559,
2609,8625,0928,9690,8284,4805,3344,
4213,7593,1858,4019,9067,0522,5465,
6582,4741,0261,2557,7016,7294,3515,
8169,0757,8442,2629,1492,8930,2388,
4704,1350,9631,0012,8605,4326,4657,
4641,9331,9307,1223,8070,9246,1994,
5674,0882,8449,0315,3840,8268,2934,
6359,3103,3994,0137,1853,4411,3541,
5134,9033,9449,0603,4242,6761,8780,
6523,9341,5951,8290,3168,7163,2769,
1756,0407,1789,1266,7394,7335,3462,
2898,2474,6007,8934,8975,3934,7338,
3597,1997,3254,6314,6932,7528,6048,
6943,0808,7340,9947,3715,0218,4721,
0649,8041,7153,7940,4937,7300,7335,
0264,7289,4675,7092,3915,5842,6801,
4637,0526,7284,8796,5720,0495,2915,
9338,3204,2810,7157,1718,9998,9106,
0480,5520,0456,6094,0467,2488,4302,
5286,4936,2184,7855,0458,3566,4202,
1556,3446,6998,4760,9067,6716,3410,
5608,9739,2996,1362,0477,4136,6232,
9769,0669,2158,6634,2988,4875,9570,
6250,7355,1680,8401,2382,9008,0001