簡單的計算題

A=999999995*1000000005 B=999999992*1000000008
求A-B=？
很簡單

回應

quietroit

Re: 簡單的計算題

2005-07-01 01:00

39

j7631103

Re: 簡單的計算題

2005-07-01 12:36

沒錯

j7631103

Re: 簡單的計算題

2005-07-01 12:42

過程A=(1000000000-5)*(1000000000+5)=1000000000^2-25
過程B=(1000000000-8)*(1000000000+8)=1000000000^2-64
所以A-B等於
-25-(-64)=-25+64=39

j7631103

Re: 簡單的計算題

2005-07-01 13:37

以後可否附上過程

Kiyokawa

Re: 簡單的計算題

2007-01-26 17:43

A-B
=(999999992+3)*1000000005-999999992*(1000000005+3)
=999999992*1000000005+3*1000000005-999999992*1000000005-999999992*3
=1000000005*3-999999992*3
=13*3
=39

gcobc36557

Re: 簡單的計算題

2007-02-08 13:57

A:39
(小算盤真好用) :-o

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jerry811215

Re: 簡單的計算題

2007-02-08 14:18

利用a^2 - b^2 就好啦!! :-)

:-)

7A蘇大岡

Re: 簡單的計算題

2007-02-12 17:29

(1000000000-5*1000000000+5)-(1000000000-8*1000000000+8)=-25-(-64)=39

jacob821102

Re: 簡單的計算題

2007-02-23 18:09

39

wen22803834

Re: 簡單的計算題

2007-02-23 22:52

39