(xy+1)(x+1)(y+1)+xy=0

回應

2009-01-11 22:02
(xy+1)(x+1)(y+1)+xy
=(xy+1)(xy+x+y+1)+xy
=(xy+1)(xy+1+x+y)+xy
=(xy+1)^2+(xy+1)(x+y)+xy (用十字交乘法)
=(xy+1+x)(xy+1+y)