1.d/dx { (x^2-1)[x^(ln x)^(cos x)^(x) +4x][2x^4 -sin(x-2)]=

2.鋛e^(sin x) cos x dx=

3.鋛[2x-3(x^2) +1]^(9x-4) dx=

4.d/dx{ (2x-1)[3(x^2)-4sin(x-1)]-鋛(2x-1)(6x-4cos(x-1) dx }=
;-)