f [(1+x)/x] ={[(x^2)+1]/x} + 1/x Find f (x^3)國中 回應 訪客 (未驗證) Re: Simple question 2004-08-25 11:09 設1+x/x=t 則x=1/t-1 f [t]={[(1/t-1)^2+1]*(t-1)}+t-1 再將x^3帶入即可
訪客 (未驗證) Re: Simple question 2004-08-25 11:09 設1+x/x=t 則x=1/t-1 f [t]={[(1/t-1)^2+1]*(t-1)}+t-1 再將x^3帶入即可
回應
訪客 (未驗證)
Re: Simple question
2004-08-25 11:09則x=1/t-1
f [t]={[(1/t-1)^2+1]*(t-1)}+t-1
再將x^3帶入即可