請問
1. (x-2)x小於-1 ,大於等於1 ,求X的範圍?

2. 若一數列a_n,a_1等於1,則(a_(n+1))等於(a_n)/2+1,求a_n等於多少?

回應

2006-10-05 15:10
不好意思~~

我需要完整的解題程式~~

= =

2006-10-05 23:44
a_n
=(a_(n-1))/2+1
=((a_(n-2)/2+1)/2+1
=...
=a_1/2^n+a_1/2^(n-1)+a_1/2^(n-2)+...+1
=(1-1/2^n)/(1-1/2)
=2-(1/2)^(n-1)