證明有無窮多個正整數不能表為三個立方數之和。國中 回應 訪客 (未驗證) Re: How? 2004-03-09 20:14 N≡0,1,2,3,4,5,6,7(mod8) N^3≡0,1,8,27,64,125,216,343 ≡0,1,0,3,0,5,0,7≡0,1,3,5,7(mod8) 任取3數,令其和為S S={0,3,9,15,21,1,3,5,7,5,7,9,11,13,17,1,7,13,19,4,6,8,9,11,15} ≡{0, 3, 1, 7, 5, 1, 3, 5, 7, 5, 7, 1, 3, 5, 1, 1, 7, 5, 3, 4, 6, 0, 1, 3, 7}(mod8) 因2沒出現,所以只要是8的倍數加2都不會是任3立方數的和 故本題得證 yl871809 Re: How? 2004-03-09 23:03 不錯!! 訪客 (未驗證) Re: How? 2004-03-10 07:10 8*1+2=2^3+1^3+1^3 訪客 (未驗證) Re: How? 2004-03-10 07:10 Try to consider 8N+7 JG25208 Re: How? 2004-03-28 17:26 ㄛ!
訪客 (未驗證) Re: How? 2004-03-09 20:14 N≡0,1,2,3,4,5,6,7(mod8) N^3≡0,1,8,27,64,125,216,343 ≡0,1,0,3,0,5,0,7≡0,1,3,5,7(mod8) 任取3數,令其和為S S={0,3,9,15,21,1,3,5,7,5,7,9,11,13,17,1,7,13,19,4,6,8,9,11,15} ≡{0, 3, 1, 7, 5, 1, 3, 5, 7, 5, 7, 1, 3, 5, 1, 1, 7, 5, 3, 4, 6, 0, 1, 3, 7}(mod8) 因2沒出現,所以只要是8的倍數加2都不會是任3立方數的和 故本題得證
回應
訪客 (未驗證)
Re: How?
2004-03-09 20:14N^3≡0,1,8,27,64,125,216,343
≡0,1,0,3,0,5,0,7≡0,1,3,5,7(mod8)
任取3數,令其和為S
S={0,3,9,15,21,1,3,5,7,5,7,9,11,13,17,1,7,13,19,4,6,8,9,11,15}
≡{0, 3, 1, 7, 5, 1, 3, 5, 7, 5, 7, 1, 3, 5, 1, 1, 7, 5, 3, 4, 6, 0, 1, 3, 7}(mod8)
因2沒出現,所以只要是8的倍數加2都不會是任3立方數的和
故本題得證
yl871809
Re: How?
2004-03-09 23:03訪客 (未驗證)
Re: How?
2004-03-10 07:10訪客 (未驗證)
Re: How?
2004-03-10 07:10JG25208
Re: How?
2004-03-28 17:26