如何求幾位數呀= =國中 回應 honnnman Re: 2的222次方 2004-09-12 15:37 First , we have 1 = 10^0 and 9 = 10^(0.xxxxx...) So we know if there is an integer which have "n" digits . It is equal to 10^ (n-1).xxxxxxx...... ((n-1) is the integer part) log2^222 =222*log2 =222*0.3130xxxx... =66.828xxxxx So 2^222 have 67 digits.
honnnman Re: 2的222次方 2004-09-12 15:37 First , we have 1 = 10^0 and 9 = 10^(0.xxxxx...) So we know if there is an integer which have "n" digits . It is equal to 10^ (n-1).xxxxxxx...... ((n-1) is the integer part) log2^222 =222*log2 =222*0.3130xxxx... =66.828xxxxx So 2^222 have 67 digits.
回應
honnnman
Re: 2的222次方
2004-09-12 15:37So we know if there is an integer which have "n" digits . It is equal to 10^ (n-1).xxxxxxx...... ((n-1) is the integer part)
log2^222
=222*log2
=222*0.3130xxxx...
=66.828xxxxx
So 2^222 have 67 digits.