求f(X)=1/2(10^x-10^-x)的反函數 國中 回應 jhshieh Re: HELP!! 2005-01-08 13:44 引用： 寫道: 求f(X)=1/2(10^x-10^-x)的反函數 訪客 (未驗證) Re: HELP!! 2005-01-09 09:37 為何2yz=z^2-1會得到z=y+y^2+1[y^2+1開根號] goodshawn12 Re: HELP!! 2005-01-09 21:46 2yz=z^2 - 1 z^2 - 2yz=1 z^2 - 2yz + y^2 =1+y^2 (z - y)^2=1+y^2 z=y+根號(y^2+1)
goodshawn12 Re: HELP!! 2005-01-09 21:46 2yz=z^2 - 1 z^2 - 2yz=1 z^2 - 2yz + y^2 =1+y^2 (z - y)^2=1+y^2 z=y+根號(y^2+1)
回應
jhshieh
Re: HELP!!
2005-01-08 13:44訪客 (未驗證)
Re: HELP!!
2005-01-09 09:37goodshawn12
Re: HELP!!
2005-01-09 21:46z^2 - 2yz=1
z^2 - 2yz + y^2 =1+y^2
(z - y)^2=1+y^2
z=y+根號(y^2+1)