(1-1/2+1/3-1/4+...-1/100)/(1/102+1/104+1/106+...+1/200)=?
:-?
國中

回應

訪客 (未驗證)

2005-10-15 20:05
ANS: ２
....................
(1-1/2+1/3-1/4+...-1/100)/(1/102+1/104+1/106+...+1/200)
=[(1+1/2+1/3+...+1/100)-2[1/2+1/4+1/6+....+1/100)] /[1/2(1/51+1/52+1/53+...+1/100)]
=[1+1/2+1/3+....+1/100-(1/1+1/2+1/3+...+1/50)]/[1/2(1/51+1/52+....+1/100)]
=[1/51+1/52+1/53+....+1/100]/[1/2(1/51+1/52+...+1/100)]
=2

哇~分數好難用電腦表示...不知道這樣看不看的懂
THE END