4^2-1/3^2 X 5^2-1/4^2 X 6^2-1/5^2 x~~~~~~~~~~~~~~~~25^2-1/24^2=??

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2006-03-09 21:11
是"(4^2-1)/3^2 X (5^2-1)/4^2 X (6^2-1)/5^2 x~~~~~~~~~~~~~~~~(25^2-1)/24^2=??"嗎?

2006-03-09 22:45
應該是這樣
原式=(4-1)(4+1)/3^2 X(5-1)(5+1)/4^2 X(6-1)(6+1)/5^2 X...... X(24-1)(24+1)/23^2 X(25-1)(25+1)/24^2
=5/3+6/4+7/5+......+25/23+26/24
=(1+2/3)+(1+2/4)+......+(1+2/23)+(1+2/24)
=22+2(1/3+1/4+1/5+......+1/23+1/24)

數字有點不好算,不知道有沒有更簡單明瞭的式子 :-? :-?

2006-03-14 21:38
4-1)(4+1)/3^2 X(5-1)(5+1)/4^2 X(6-1)(6+1)/5^2 X...... X(24-1)(24+1)/23^2 X(25-1)(25+1)/24^2
=5/3+6/4+7/5+......+25/23+26/24
=(1+2/3)+(1+2/4)+......+(1+2/23)+(1+2/24)
=22+2(1/3+1/4+1/5+......+1/23+1/24)

先把它用乘法攻是做好是對了旦我所說的是全部城起來為何第二個等號出現了+法呢!?